-a^2-19a-88=0

Solution for -a^2-19a-88=0 equation:

-a^2-19a-88=0

We add all the numbers together, and all the variables

-1a^2-19a-88=0

a = -1; b = -19; c = -88;
Δ = b2-4ac
Δ = -192-4·(-1)·(-88)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-3}{2*-1}=\frac{16}{-2}
=-8
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+3}{2*-1}=\frac{22}{-2}
=-11
$